Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.
Example 1:
Input: "Let's take LeetCode contest"
Output: "s'teL ekat edoCteeL tsetnoc"
Note: In the string, each word is separated by single space and there will not be any extra space in the string.
难度: easy
题目:给定字符串,返转字符串中的单词,保留空格和单词顺序。
思路:遍历,返转
Runtime: 11 ms, faster than 50.54% of Java online submissions for Reverse Words in a String III.
Memory Usage: 38.7 MB, less than 96.70% of Java online submissions for Reverse Words in a String III.
class Solution { public String reverseWords(String s) { s = " " + s + " "; StringBuilder result = new StringBuilder(); int begin = 0, end = 0; for (int i = 1; i < s.length() - 1; i++) { char c = s.charAt(i); if (c != ' ' && s.charAt(i - 1) == ' ') { begin = i; result.append(s.substring(end + 1, begin)); } if (c != ' ' && s.charAt(i + 1) == ' ') { end = i; for (int j = end; j >= begin; j--) { result.append(s.charAt(j)); } } } return result.toString(); } }